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Inverse of 1435th cyclotomic polynomial.
5

%I #15 Jun 02 2020 14:01:17

%S 1,-1,0,0,0,1,-1,1,-1,0,1,-1,1,-1,1,0,-1,1,-1,1,0,0,0,-1,1,0,0,0,0,0,

%T 0,0,0,0,0,0,0,0,0,0,0,1,-1,0,0,0,1,-1,1,-1,0,1,-1,1,-1,1,0,-1,1,-1,1,

%U 0,0,0,-1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0

%N Inverse of 1435th cyclotomic polynomial.

%C Periodic with period length 1435. - _Ray Chandler_, Apr 07 2017

%H Ray Chandler, <a href="/A015444/b015444.txt">Table of n, a(n) for n = 0..2000</a>

%H <a href="/index/Rec#order_960">Index entries for linear recurrences with constant coefficients</a>, order 960.

%H <a href="/index/Pol#poly_cyclo_inv">Index to sequences related to inverse of cyclotomic polynomials</a>

%p with(numtheory,cyclotomic); c := n->series(1/cyclotomic(n,x),x,80);

%t CoefficientList[Series[1/Cyclotomic[1435,x],{x,0,100}],x] (* _Harvey P. Dale_, Jun 02 2020 *)

%o (PARI) Vec(1/polcyclo(1435)+O(x^99)) \\ _Charles R Greathouse IV_, Mar 24 2014

%K sign

%O 0,1

%A _Simon Plouffe_