%I #19 Jun 01 2026 18:43:25
%S 1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
%T 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
%U 0,0,0,0,0,0,0,0,0,0,0,0,0
%N Inverse of 1111th cyclotomic polynomial.
%C Periodic with period length 1111. - _Ray Chandler_, Apr 07 2017
%H Ray Chandler, <a href="/A015120/b015120.txt">Table of n, a(n) for n = 0..2000</a>
%H <a href="/index/Per#periodic">Index entries for periodic sequences</a>, period 1111.
%H <a href="/index/Rec#order_1000">Index entries for linear recurrences with constant coefficients</a>, order 1000.
%H <a href="/index/Pol#poly_cyclo_inv">Index to sequences related to inverse of cyclotomic polynomials</a>
%p with(numtheory,cyclotomic); c := n->series(1/cyclotomic(n,x),x,80);
%t CoefficientList[Series[1/Cyclotomic[1111,x],{x,0,12}],x,120] (* _Harvey P. Dale_, Sep 12 2023 *)
%o (PARI) first(n)=Vec(1/polcyclo(1111)+O(x^(n+1))) \\ _Charles R Greathouse IV_, Jun 01 2026
%K sign,easy
%O 0,1
%A _Simon Plouffe_