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a(n) = (n-1)^a(1) + (n-2)^a(2) + (n-3)^a(3) + ... + 1^a(n-1).
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%I #11 Jul 05 2021 14:47:15

%S 1,1,3,6,16,101,66341,2535301200456458802993449461708

%N a(n) = (n-1)^a(1) + (n-2)^a(2) + (n-3)^a(3) + ... + 1^a(n-1).

%K nonn

%O 1,3

%A _Jon Wild_, Jul 14 1997