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a(n) = ceiling((n+1/n)^n).
25

%I #19 Sep 08 2022 08:44:39

%S 2,7,38,327,3803,54993,948646,18992711,432655359,11046221255,

%T 312347907387,9688154906658,327018557066165,11932588574197764,

%U 468012768020438831,19634066192684343923,877272066059957914874

%N a(n) = ceiling((n+1/n)^n).

%H Vincenzo Librandi, <a href="/A014058/b014058.txt">Table of n, a(n) for n = 1..300</a>

%t Table[Ceiling[(n+1/n)^n],{n,20}] (* _Harvey P. Dale_, Jul 09 2017 *)

%o (Magma) [Ceiling((n+1/n)^n): n in [1..20]]; // _Vincenzo Librandi_, Oct 18 2011

%o (PARI) a(n)=ceil((n+1/n)^n) \\ _Charles R Greathouse IV_, Jul 01 2013

%o (Sage) [ceil((n+1/n)^n) for n in (1..20)] # _G. C. Greubel_, Nov 23 2018

%Y Cf. A014052, A014056.

%K nonn

%O 1,1

%A _N. J. A. Sloane_