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22^(5n+4).
1

%I #17 Sep 08 2022 08:44:38

%S 234256,1207269217792,6221821273427820544,32064977213018365645815808,

%T 165251092644282265779977014214656,

%U 851643319086537701956194499721106030592,4389056261830591470007906571986683114651910144,22619580800770514778759787562400873673529752979243008

%N 22^(5n+4).

%H Vincenzo Librandi, <a href="/A013905/b013905.txt">Table of n, a(n) for n = 0..50</a>

%H Tanya Khovanova, <a href="http://www.tanyakhovanova.com/RecursiveSequences/RecursiveSequences.html">Recursive Sequences</a>

%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (5153632).

%F a(n) = 5153632*a(n-1), a(0)=234256. - _Vincenzo Librandi_, May 28 2011

%F a(n) = 22^A016897(n) = A010810(5n+4) = A010810(A016897(n)). - _Wesley Ivan Hurt_, May 08 2014

%p A013905:=n->22^(5*n+4); seq(A013905(n), n=0..10); # _Wesley Ivan Hurt_, May 08 2014

%t Table[22^(5 n + 4), {n, 0, 10}] (* _Wesley Ivan Hurt_, May 08 2014 *)

%o (Magma) [22^(5*n+4): n in [0..10]]; // _Vincenzo Librandi_, May 28 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_, Dec 11 1996