%I #6 Mar 30 2012 16:45:33
%S 4,2,1,9,3,3,93,4,4,1,2,3,2,7,1,2,2,5,1,1,1,2,1,3,4,4,4,217,4,2,1,1,1,
%T 3,1,4,51,45,10,1,6,1,2,4,1,2,2,1,5,11,1,4,1,1,3,3,1,2,128,5,1,1,5,4,
%U 1,43,1,4,15,5,1,2,1,3,1,15
%N Continued fraction for cube root of 82.
%H G. Xiao, <a href="http://wims.unice.fr/~wims/en_tool~number~contfrac.en.html">Contfrac</a>
%K nonn,cofr
%O 0,1
%A _N. J. A. Sloane_.