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%I #14 Apr 13 2021 00:24:39
%S 2,4,2,6,1,1,2,1,2,9,88,2,1,2,1,8,1,1,3,4,1,7,1,40,1,1,36,2,3,1,29,6,
%T 3,1,2,2,5,1,4,1,10,5,1,2,1,1,1,88,4,4,3,5,3,7,1,1,17,5,4,3,4,3,5,1,5,
%U 103,1,1,1,12,4,1,1,4,1,1
%N Continued fraction for cube root of 11.
%H Robert Israel, <a href="/A010241/b010241.txt">Table of n, a(n) for n = 0..10000</a>
%H G. Xiao, <a href="http://wims.unice.fr/~wims/en_tool~number~contfrac.en.html">Contfrac</a>
%p numtheory:-cfrac(11^(1/3),100,'quotients'); # _Robert Israel_, Apr 12 2021
%t ContinuedFraction[11^(1/3),80] (* _Harvey P. Dale_, Mar 25 2012 *)
%K nonn,cofr
%O 0,1
%A _N. J. A. Sloane_