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Continued fraction for sqrt(141).
0

%I #25 Nov 15 2023 01:13:31

%S 11,1,6,1,22,1,6,1,22,1,6,1,22,1,6,1,22,1,6,1,22,1,6,1,22,1,6,1,22,1,

%T 6,1,22,1,6,1,22,1,6,1,22,1,6,1,22,1,6,1,22,1,6,1,22,1,6,1,22,1,6,1,

%U 22,1,6,1,22,1,6,1,22,1,6,1

%N Continued fraction for sqrt(141).

%H G. Xiao, <a href="http://wims.unice.fr/~wims/en_tool~number~contfrac.en.html">Contfrac</a>.

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,1).

%F From _Amiram Eldar_, Nov 15 2023: (Start)

%F Multiplicative with a(2) = 6, a(2^e) = 22 for e >= 2, and a(p^e) = 1 for an odd prime p.

%F Dirichlet g.f.: zeta(s) * (1 + 5/2^s + 1/4^(s-2)). (End)

%t ContinuedFraction[Sqrt[141],300] (* _Vladimir Joseph Stephan Orlovsky_, Mar 13 2011 *)

%K nonn,cofr,easy,mult

%O 0,1

%A _N. J. A. Sloane_