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Infinitesimal generator of x*(x + 1).
(Formerly M3024)
3

%I M3024 #35 Feb 15 2019 09:14:56

%S 1,1,3,16,124,1256,15576,226248,3729216,68179968,1361836800,

%T 29501349120,693638208000,17815908096000,502048890201600,

%U 15388268595840000,500579319427891200,16817771937344716800,581609175119297740800

%N Infinitesimal generator of x*(x + 1).

%C From _Peter Bala_, Dec 09 2015: (Start)

%C Given a formal power series f(x) = x + f_2*x^2 + f_3*x^3 + ... Labelle [Section 4, Proposition 4] shows there is a power series w(x) = w_2*x^2 + w_3*x^3 + w_4*x^4 + ..., called the infinitesimal generator of f, such that the n-fold composition f^(n)(x) = f o f o ... o f (n factors) of f(x) is given by the operator exp( n*w(x)*d/dx ) acting on x. This gives the expansion f^(n)(x) = x + n/1!*w(x) + n^2/2!*w(x)*w'(x) + .... Taking n = -1 gives an expansion for the series reversion of f(x).

%C Let R denote the Riordan array (f(x)/x, f(x)). Then the coefficients of the infinitesimal generator w(x) form the first column of the matrix logarithm log(R).

%C Here we take f(x) = x + x^2 and calculate w(x) = x^2*(1 - x + 3*x^2/2! - 16*x^3/3! + 124*x^4/4! - ...). The numerators of the coefficients give a signed version of the present sequence. See the example below. (End)

%C a(29) = -307081193389527408920486163460915200000 is the first negative term. _Georg Fischer_, Feb 15 2019

%D N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

%H G. C. Greubel, <a href="/A005119/b005119.txt">Table of n, a(n) for n = 1..200</a>

%H Gilbert Labelle, <a href="http://dx.doi.org/10.1016/S0195-6698(80)80047-3">Sur l'Inversion et l'Iteration Continue des Séries Formelles</a>, European Journal of Combinatorics, Vol. 1 Issue 2 (June 1980), 113-138.

%F a(n) = (n-2)!*Sum_{i=1..n-1} (-1)^(i+1)*C(n-i+1,i+1)*a(n-i)/(n-i-1)! for n>1 with a(1)=1. E.g.f. satisfies: A(x) = (1-x)^2/(1-2x)*A(x-x^2) where A(x) = Sum_{n>=0}a(n+1)*x^n/n! with offset so that A(0)=1. - _Paul D. Hanna_, Dec 27 2007

%e From _Peter Bala_, Dec 09 2015: (Start)

%e The Riordan array R = (1 + x, x*(1 + x)) is A030528.

%e log(R) begins

%e / 0

%e | 1 0

%e | -1 1*2 0

%e | 3/2! -1*2 1*3 0

%e |-16/3! (3/2!)*2 -1*3 1*4 0

%e |124/4! (-16/3!)*2 (3/2!)*3 -1*4 1*5 0

%e |...

%e \

%e The first column begins [1, -1, 3/2!, -16/3! 124/4!, ...]. (End)

%t max = 19; f[x_] := Sum[a[n+1]*x^n/n!, {n, 0, max}]; coes = CoefficientList[ Series[ f[x]-((1-x)^2/(1-2*x))*f[x-x^2], {x, 0, max}], x]; Array[a, max] /. Solve[a[1] == a[2] == 1 && Thread[coes == 0]][[1]] (* _Jean-François Alcover_, Nov 03 2011 *)

%t nmax=20; a = ConstantArray[0,nmax]; a[[1]]=1; Do[a[[n]] = (n-2)! *Sum[(-1)^(i+1)*Binomial[n-i+1,i+1]*a[[n-i]]/(n-i-1)!,{i,1,n-1}],{n,2,nmax}]; a (* _Vaclav Kotesovec_, Mar 12 2014 *)

%o (PARI) {a(n)=if(n<1,0,if(n==1,1,(n-2)!*sum(i=1,n-1,(-1)^(i+1)*binomial(n-i+1,i+1)*a(n-i)/(n-i-1)!)))} \\ _Paul D. Hanna_, Dec 27 2007

%Y Cf. A030528.

%K sign,nice

%O 1,3

%A _N. J. A. Sloane_, _Simon Plouffe_

%E More terms from _Paul D. Hanna_, Dec 27 2007