OFFSET
0,1
COMMENTS
The probability distribution function of disorientation angles was calculated for random rotations uniformly distributed with respect to Haar measure (see, e.g., Rummler, 2002).
See A361601 for more details.
The angle in degrees is 40.7358443613...
LINKS
Amiram Eldar, Mathematica code for A361602, A361603 and A361604.
D. C. Handscomb, On the random disorientation of two cubes, Canadian Journal of Mathematics, Vol. 10 (1958), pp. 85-88.
J. K. Mackenzie, Second Paper on Statistics Associated with the Random Disorientation of Cubes, Biometrika, Vol. 45, No. 1-2 (1958), pp. 229-240.
J. K. Mackenzie and M. J. Thomson, Some Statistics Associated with the Random Disorientation of Cubes, Biometrika, Vol. 44, No. 1-2 (1957), pp. 205-210.
Hansklaus Rummler, On the distribution of rotation angles how great is the mean rotation angle of a random rotation?, The Mathematical Intelligencer, Vol. 24, No. 4 (2002), pp. 6-11; alternative link.
Wikipedia, Misorientation.
FORMULA
Equals Integral_{t=0..tmax) t * P(t) dt, where tmax = A361601 and P(t) is
1) (24/Pi) * (1-cos(t)) for 0 <= t <= Pi/4.
2) (24/Pi) * (3*(sqrt(2)-1)*sin(t) - 2*(1-cos(t))) for Pi/4 <= t <= Pi/3.
3) (24/Pi) * ((3*(sqrt(2)-1) + 4/sqrt(3)) * sin(t) - 6*(1-cos(t))) for Pi/3 <= t <= 2 * arctan(sqrt(2) * (sqrt(2)-1)).
4) (24/Pi) * ((3*(sqrt(2)-1) + 4/sqrt(3)) * sin(t) - 6*(1-cos(t))) - (288*sin(t)/Pi^2) * (2*(sqrt(2)-1) * arccos(f(t) * cot(t/2)) + (1/sqrt(3)) * arccos(g(t) * cot(t/2))) + (288*(1-cos(t))/Pi^2) * (2*arccos(f(t) * (sqrt(2)+1)/sqrt(2)) + arccos(g(t) * (sqrt(2)+1)/sqrt(2))) for 2 * arctan(sqrt(2) * (sqrt(2)-1)) <= t <= tmax, where f(t) = (sqrt(2)-1)/sqrt(1-(sqrt(2)-1)^2 * cot(t/2)^2) and g(t) = (sqrt(2) - 1)^2/sqrt(3 - cot(t/2)^2).
EXAMPLE
0.71097460768605911916438944041537014933928621039476...
MATHEMATICA
See the program in the links section.
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
Amiram Eldar, Mar 17 2023
STATUS
approved