OFFSET
0,3
COMMENTS
If row elements are divided by row sums, one obtains a probability distribution that approaches a Poisson distribution with expected value 1 as n approaches infinity.
FORMULA
T(n,k) equals 2^k times the corresponding element of the triangle of A168422.
T(n,k) = 2^k * Sum_{j=k..n} (-1)^(j-k) * C(2*n-j,n) * C(n,j) * C(j,k) * (n-j)!.
Recurrence: T(n,k) = (1/k!) * Sum_{j=0..k} T(n-j,0) * (-1)^j * C(k,j) * Sum_{t=0..min(j,k-j)} (-1)^(j-t) * C(j,t) * (k-j)! / (k-j-t)!
= (1/k!) * Sum_{j=0..k} T(n-j,0) * (-1)^j * C(k,j) * R(k,j) where R(k,j) is an element of the triangle of A253667.
EXAMPLE
Triangle begins:
1
1 2
7 8 4
71 78 36 8
1001 1072 504 128 16
18089 19090 9080 2480 400 32
398959 417048 199980 56960 10320 1152 64
10391023 10789982 5204556 1523480 295120 38304 3136 128
PROG
(SageMath)
def T(n, k):
return(2^k*sum((-1)^(j-k)*binomial(2*n-j, n)*binomial(n, j)\
*binomial(j, k)*factorial(n-j) for j in range(k, n+1)))
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
William P. Orrick, Mar 08 2023
STATUS
approved