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A349294
Numbers m such that there exists a permutation p of {1,2,...,m} with p(k) dividing p(k+1) + p(k+2) for all k in {1,2,...,m-2}.
1
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 34, 37, 38, 51
OFFSET
1,2
COMMENTS
Numbers m such that A349288(m) > 0.
LINKS
V. S. Guba, Problem of the day-13, 2021. (in Russian)
EXAMPLE
m=9 belongs to this sequence since the permutation p = (1, 3, 8, 7, 9, 5, 4, 6, 2) satisfies the condition.
CROSSREFS
Cf. A349288.
Sequence in context: A109425 A357873 A226537 * A153679 A273887 A194906
KEYWORD
nonn,hard,more
AUTHOR
Max Alekseyev, Nov 13 2021
STATUS
approved