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A345687
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For 1<=x<=n, 1<=y<=n, write gcd(x,y) = u*x+v*y with u,v minimal; a(n) = n^4*s, where s is the population variance of the values of u.
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12
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0, 3, 32, 112, 500, 944, 3072, 5872, 12168, 19004, 40552, 59031, 109992, 152872, 221900, 315420, 513266, 658163, 1006272, 1277375, 1675544, 2121979, 3036460, 3652047, 4848004, 5918355, 7505768, 9012071, 11937118, 13778600, 17866848, 21132736, 25249454, 29499603
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OFFSET
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1,2
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COMMENTS
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The factor n^4 is to ensure that a(n) is an integer.
A345426(n) = n^2*mu where mu is the mean of the values of u.
The population standard deviation sqrt(s) appears to grow linearly with n.
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LINKS
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PROG
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(Python)
from statistics import pvariance
from sympy.core.numbers import igcdex
def A345687(n): return pvariance(n**2*u for u, v, w in (igcdex(x, y) for x in range(1, n+1) for y in range(1, n+1)))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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