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A bisection of A000201: a(n) = A000201(2*n+1).
2

%I #26 Aug 10 2022 02:59:55

%S 1,4,8,11,14,17,21,24,27,30,33,37,40,43,46,50,53,56,59,63,66,69,72,76,

%T 79,82,85,88,92,95,98,101,105,108,111,114,118,121,124,127,131,134,137,

%U 140,144,147,150,153,156,160,163,166,169,173,176,179,182,186,189

%N A bisection of A000201: a(n) = A000201(2*n+1).

%H N. J. A. Sloane, <a href="/A115004/a115004.txt">Families of Essentially Identical Sequences</a>, Mar 24 2021 (Includes this sequence)

%o (Python)

%o import math

%o phi = (1 + math.sqrt(5))/2

%o for n in range(101):

%o print(int(math.floor((2*n)+ 1) * phi), end=',')

%o # _Alvin Hoover Belt_, Mar 17 2021

%o (Python)

%o from math import isqrt

%o def A342279(n): return ((m:=(n<<1)+1)+isqrt(5*m**2)>>1) # _Chai Wah Wu_, Aug 10 2022

%Y Cf. A000201, A276854.

%K nonn

%O 0,2

%A _N. J. A. Sloane_, Mar 16 2021