

A000201


Lower Wythoff sequence (a Beatty sequence): a(n) = floor(n*phi), where phi = (1+sqrt(5))/2 = A001622.
(Formerly M2322 N0917)


205



1, 3, 4, 6, 8, 9, 11, 12, 14, 16, 17, 19, 21, 22, 24, 25, 27, 29, 30, 32, 33, 35, 37, 38, 40, 42, 43, 45, 46, 48, 50, 51, 53, 55, 56, 58, 59, 61, 63, 64, 66, 67, 69, 71, 72, 74, 76, 77, 79, 80, 82, 84, 85, 87, 88, 90, 92, 93, 95, 97, 98, 100, 101, 103, 105, 106, 108, 110
(list;
graph;
refs;
listen;
history;
text;
internal format)



OFFSET

1,2


COMMENTS

This is the unique sequence a satisfying a'(n)=a(a(n))+1 for all n in the set N of natural numbers, where a' denotes the ordered complement (in N) of a.  Clark Kimberling, Feb 17 2003
This sequence and A001950 may be defined as follows. Consider the maps a > ab, b > a, starting from a(1) = a; then A000201 gives the indices of a, A001950 gives the indices of b. The sequence of letters in the infinite word begins a, b, a, a, b, a, b, a, a, b, a, ... Setting a = 0, b = 1 gives A003849 (offset 0); setting a = 1, b = 0 gives A005614 (offset 0).  Philippe Deléham, Feb 20 2004
These are the numbers whose lazy Fibonacci representation (see A095791) includes 1; the complementary sequence (the upper Wythoff sequence, A001950) are the numbers whose lazy Fibonacci representation includes 2 but not 1.
a(n) is the unique monotonic sequence satisfying a(1)=1 and the condition "if n is in the sequence then n+(rank of n) is not in the sequence" (e.g. a(4)=6 so 6+4=10 and 10 is not in the sequence)  Benoit Cloitre, Mar 31 2006
Write A for A000201 and B for A001950 (the upper Wythoff sequence, complement of A). Then the composite sequences AA, AB, BA, BB, AAA, AAB,...,BBB,... appear in many complementary equations having solution A000201 (or equivalently, A001950). Typical complementary equations: AB=A+B (=A003623), BB=A+2B (=A101864), BBB=3A+5B (=A134864).  Clark Kimberling, Nov 14 2007
Cumulative sum of A001468 terms.  Eric Angelini, Aug 19 2008
The lower Wythoff sequence also can be constructed by playing the socalled Mancalagame: n piles of total d(n) chips are standing in a row. The piles are numbered from left to right by 1, 2, 3, ... . The number of chips in a pile at the beginning of the game is equal to the number of the pile. One step of the game is described as follows: Distribute the pile on the very left one by one to the piles right of it. If chips are remaining, build piles out of one chip subsequently to the right. After f(n) steps the game ends in a constant row of piles. The lower Wythoff sequence is also given by n > f(n).  Roland Schroeder (florola(AT)gmx.de), Jun 19 2010
With the exception of the first term, a(n) gives the number of iterations required to reverse the list {1,2,3,...,n} when using the mapping defined as follows: remove the first term of the list, z(1), and add 1 to each of the next z(1) terms (appending 1's if necessary) to get a new list. See A183110 where this mapping is used and other references given. This appears to be essentially the Mancalatype game interpretation given by R. Schroeder above.  John W. Layman, Feb 03 2011
Also row numbers of A213676 starting with an even number of zeros.  Reinhard Zumkeller, Mar 10 2013


REFERENCES

M. Bunder and K. Tognetti, On the self matching properties of [j tau], Discrete Math., 241 (2001), 139151.
L. Carlitz, R. Scoville and T. Vaughan, Some arithmetic functions related to Fibonacci numbers, Fib. Quart., 11 (1973), 337386.
I. G. Connell, Some properties of Beatty sequences I, Canad. Math. Bull., 2 (1959), 190197.
P. J. Downey and R. E. Griswold, On a family of nested recurrences, Fib. Quart., 22 (1984), 310317.
A. S. Fraenkel, The bracket function and complementary sets of integers, Canad. J. Math., 21 (1969), 627. [History, references, generalization]
A. S. Fraenkel, How to beat your Wythoff games' opponent on three fronts, Amer. Math. Monthly, 89 (1982), 353361 (the case a=1).
M. Gardner, Penrose Tiles to Trapdoor Ciphers, W. H. Freeman, 1989; see p. 107.
David Garth and Adam Gouge, Affinely SelfGenerating Sets and Morphisms, Journal of Integer Sequences, Vol. 10 (2007), Article 07.1.5.
A. M. Gleason et al., The William Lowell Putnam Mathematical Competition: Problems and Solutions 19381964, Math. Assoc. America, 1980, pp. 513514.
M. Griffiths, The Golden String, Zeckendorf Representations, and the Sum of a Series, Amer. Math. Monthly, 118 (2011), 497507.
H. Grossman, A set containing all integers, Amer. Math. Monthly, 69 (1962), 532533.
Clark Kimberling, Complementary equations and Wythoff sequences, Journal of Integer Sequences 11 (2008, Article 08.3.3) 18.
Clark Kimberling, Complementary Equations, Journal of Integer Sequences, 10 (2007), Article 07.1.4.
D. J. Newman, Problem 5252, Amer. Math. Monthly, 72 (1965), 11441145. Problem 3117, Amer. Math. Monthly, 34 (1927), 158159.
N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
K. B. Stolarsky, Beatty sequences, continued fractions and certain shift operators, Canad. Math. Bull., 19 (1976), 473482.
X. Sun, Wythoff's sequence ..., Discr. Math., 300 (2005), 180195.
J. C. Turner, The alpha and the omega of the Wythoff pairs, Fib. Q., 27 (1989), 7686.
I. M. Yaglom, Two games with matchsticks, pp. 17 of Qvant Selecta: Combinatorics I, Amer Math. Soc., 2001.


LINKS

N. J. A. Sloane, The first 10000 terms
J.P. Allouche, J. Shallit and G. Skordev, Selfgenerating sets, integers with missing blocks and substitutions, Discrete Math. 292 (2005) 115.
Joerg Arndt, Matters Computational (The Fxtbook), pp.756757
Shiri ArtsteinAvidan, Aviezri S. Fraenkel and Vera T. Sos, A twoparameter family of an extension of Beatty, Discr. Math. 308 (2008), 45784588.
Shiri Artsteinavidan, Aviezri S. Fraenkel and Vera T. Sos, A twoparameter family of an extension of Beatty sequences, Discrete Math., 308 (2008), 45784588.
E. J. Barbeau, J. Chew and S. Tanny, A matrix dynamics approach to Golomb's recursion, Electronic J. Combinatorics, #4.1 16 1997.
B. Cloitre, N. J. A. Sloane and M. J. Vandermast, Numerical analogues of Aronson's sequence, J. Integer Seqs., Vol. 6 (2003), #03.2.2.
B. Cloitre, N. J. A. Sloane and M. J. Vandermast, Numerical analogues of Aronson's sequence (math.NT/0305308)
J. H. Conway and N. J. A. Sloane, Notes on the ParaFibonacci and related sequences
N. Fox, On Aperiodic Subtraction Games with Bounded Nim Sequence, arXiv preprint arXiv:1407.2823, 2014
A. S. Fraenkel, Ratwyt, December 28 2011.
C. Kimberling, A SelfGenerating Set and the Golden Mean, J. Integer Sequences, 3 (2000), #00.2.8.
C. Kimberling, Matrix Transformations of Integer Sequences, J. Integer Seqs., Vol. 6, 2003.
Clark Kimberling, Problem Proposals, The Fibonacci Quarterly, vol. 52 #5, 2015, p514.
Vincent Russo and Loren Schwiebert, Beatty Sequences, Fibonacci Numbers, and the Golden Ratio, The Fibonacci Quarterly, Vol 49, Number 2, May 2011.
N. J. A. Sloane, My favorite integer sequences, in Sequences and their Applications (Proceedings of SETA '98).
N. J. A. Sloane, Classic Sequences
Richard Southwell and Jianwei Huang, Complex Networks from Simple Rewrite Systems, arXiv preprint arXiv:1205.0596, 2012.  N. J. A. Sloane, Oct 13 2012
Eric Weisstein's World of Mathematics, Beatty Sequence
Eric Weisstein's World of Mathematics, Golden Ratio
Eric Weisstein's World of Mathematics, Rabbit Constant
Eric Weisstein's World of Mathematics, Wythoff's Game
Eric Weisstein's World of Mathematics, Wythoff Array
Index entries for sequences related to Beatty sequences
Index entries for sequences of the a(a(n)) = 2n family


FORMULA

Zeckendorf expansion of n (cf. A035517) ends with an even number of 0's.
Other properties: a(1)=1; for n>1, a(n) is taken to be the smallest integer greater than a(n1) which is consistent with the condition "n is in the sequence if and only if a(n)+1 is not in sequence".
a(1) = 1; for n>0, a(n+1) = a(n)+1 if n is not in sequence, a(n+1) = a(n)+2 if n is in sequence.
a(a(n)) = floor[n*phi^2]  1 = A003622(n).
{a(k)} union {a(k)+1} = {1, 2, 3, 4, ...}. Hence a(1) = 1; for n>1, a(a(n)) = a(a(n)1)+2, a(a(n)+1) = a(a(n))+1.  Benoit Cloitre, Mar 08, 2003
{a(n)} is a solution to the recurrence a(a(n)+n) = 2*a(n)+n, a(1)=1 (see Barbeau et al.).
a(n) = A001950(n)  n  Philippe Deléham, May 02 2004
a(0) = 0; a(n) = n + max{ k : a(k) < n}.  Vladeta Jovovic, Jun 11 2004
a(Fib(r1)+j) = Fib(r)+a(j) for 0<j<=Fib(r2); 2<r.  Paul Weisenhorn, Aug 18 2012
With 1 < k and A001950(k1) < n <= A001950(k): a(n) = 2*nk; A001950(n) = 3*nk.  Paul Weisenhorn, Aug 21 2012


EXAMPLE

From Roland Schroeder (florola(AT)gmx.de), Jul 13 2010: (Start)
Example for n = 5; a(5) = 8
(Start: [1,2,3,4,5]; 8 steps until [5,4,3,2,1]):
[1,2,3,4,5]; [3,3,4,5]; [4,5,6]; [6,7,1,1]; [8,2,2,1,1,1]: [3,3,2,2,2,1,1,1]; [4,3,3,2,1,1,1]; [4,4,3,2,1,1]; [5,4,3,2,1]. (End)


MAPLE

Digits := 100; t := evalf((1+sqrt(5))/2); A000201 := n>floor(t*n);


MATHEMATICA

Table[Floor[N[n*(1+Sqrt[5])/2]], {n, 1, 75}]
Array[ Floor[ #*GoldenRatio] &, 68] (* Robert G. Wilson v, Apr 17 2010 *)


PROG

(PARI) a(n)=floor(n*(sqrt(5)+1)/2)
(PARI) a(n)=(n+sqrtint(5*n^2))\2 \\ Charles R Greathouse IV, Feb 07 2013
(Maxima) makelist(floor(n*(1+sqrt(5))/2), n, 1, 60); [Martin Ettl, Oct 17 2012]
(Haskell)
a000201 n = a000201_list !! (n1)
a000201_list = f [1..] [1..] where
f (x:xs) (y:ys) = y : f xs (delete (x + y) ys)
 Reinhard Zumkeller, Jul 02 2015, Mar 10 2013


CROSSREFS

a(n) = least k such that s(k) = n, where s = A026242. Complement of A001950. See also A058066.
The permutation A002251 maps between this sequence and A001950, in that A002251(a(n)) = A001950(n), A002251(A001950(n)) = a(n).
First differences give A014675. a(n) = A022342(n) + 1 = A005206(n) + n + 1. a(2n)a(n)=A007067(n). a(a(a(n)))a(n) = A026274(n1).  Benoit Cloitre, Mar 08 2003
A185615 gives values n such that n divides A000201(n)^m for some integer m>0.
Cf. A183110.
Sequence in context: A085270 A090908 A066096 * A000202 A188035 A026339
Adjacent sequences: A000198 A000199 A000200 * A000202 A000203 A000204


KEYWORD

nonn,easy,nice


AUTHOR

N. J. A. Sloane


EXTENSIONS

Mathematica coding shortened by Robert G. Wilson v, Apr 17 2010


STATUS

approved



