OFFSET
1,2
COMMENTS
Number of digits in a(n) = A000045(n+1). - Michael S. Branicky, Apr 24 2021
a(n) and a(n+1) contain Fibonacci(n) 1's and Fibonacci(n) 0's respectively.
PROG
(Python)
def aupton(terms):
alst = [1, 10]
for n in range(3, terms+1): alst.append(int(str(alst[-2])+str(alst[-1])))
return alst[:terms]
print(aupton(10)) # Michael S. Branicky, Apr 24 2021
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Wesley Ivan Hurt, Apr 24 2021
STATUS
approved