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A333841
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Integers n such that n! = x^2 + y^3 + z^4 where x, y and z are nonnegative integers, is soluble.
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0
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0, 1, 2, 3, 4, 6, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24
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OFFSET
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1,3
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LINKS
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FORMULA
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EXAMPLE
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6! = 11^2+7^3+4^4; 8! = 192^2+15^3+3^4; 9! = 443^2+55^3+4^4; 10! = 1888^2+40^3+4^4; 11! = 5896^2+172^3+16^4, so 6, 8, 9, 10 and 11 are in the sequence. - R. J. Mathar, Dec 15 2020
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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STATUS
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approved
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