%I #72 Dec 15 2020 09:10:52
%S 0,1,2,3,4,6,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24
%N Integers n such that n! = x^2 + y^3 + z^4 where x, y and z are nonnegative integers, is soluble.
%F {k: k! in A123053}. - _R. J. Mathar_, Dec 15 2020
%e 6! = 11^2+7^3+4^4; 8! = 192^2+15^3+3^4; 9! = 443^2+55^3+4^4; 10! = 1888^2+40^3+4^4; 11! = 5896^2+172^3+16^4, so 6, 8, 9, 10 and 11 are in the sequence. - _R. J. Mathar_, Dec 15 2020
%Y Cf. A123053, A267414, A337046.
%K nonn,more
%O 1,3
%A _Altug Alkan_, Aug 14 2020