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A330899
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Numbers m such that (1/m) * Sum_{k=1..m} sigma(k)/k sets a record value, where sigma(k) is the sum of divisors of k.
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3
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1, 2, 3, 4, 6, 8, 10, 12, 16, 18, 20, 22, 24, 28, 30, 36, 42, 48, 56, 60, 72, 84, 90, 96, 100, 108, 112, 120, 144, 156, 168, 180, 192, 210, 240, 276, 280, 288, 300, 312, 324, 330, 336, 360, 396, 408, 420, 480, 528, 540, 576, 600, 630, 660, 672, 720, 756, 792
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OFFSET
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1,2
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COMMENTS
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Numbers m such that the mean of the abundancy index sigma(k)/k in the range 1..m is closer to the asymptotic mean Pi^2/6 than the mean in any smaller range.
Since (1/m) * Sum_{k=1..m} sigma(k)/k < Pi^2/6 for all m, and the limit is Pi^2/6 as m -> infinity, this sequence is infinite.
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LINKS
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EXAMPLE
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The mean abundancy in the range 1..m for m = 1, 2, ..., 6 is 1, 1.25, 1.277..., 1.395..., 1.356..., 1.463..., so the record values occur at 1, 2, 3, 4 and 6.
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MATHEMATICA
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seq = {}; s = 0; rm = 0; Do[s += DivisorSigma[1, n]/n; r = s/n; If[r > rm, rm = r; AppendTo[seq, n]], {n, 1, 1000}]; seq
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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