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A329025 If n = Product (p_j^k_j) then a(n) = concatenation (pi(p_j)), where pi = A000720. 2

%I #7 Nov 04 2019 09:22:39

%S 0,1,2,1,3,12,4,1,2,13,5,12,6,14,23,1,7,12,8,13,24,15,9,12,3,16,2,14,

%T 10,123,11,1,25,17,34,12,12,18,26,13,13,124,14,15,23,19,15,12,4,13,27,

%U 16,16,12,35,14,28,110,17,123,18,111,24,1,36,125,19,17,29,134

%N If n = Product (p_j^k_j) then a(n) = concatenation (pi(p_j)), where pi = A000720.

%C Concatenate of indices of distinct prime factors of n, in increasing order.

%H Ilya Gutkovskiy, <a href="/A329025/a329025.jpg">Scatter plot of a(n) up to n=100000</a>

%H <a href="/index/Pri#prime_indices">Index entries for sequences computed from indices in prime factorization</a>

%F a(prime(n)^k) = n for k > 0.

%e a(60) = a(2^2 * 3 * 5) = a(prime(1)^2 * prime(2) * prime(3)) = 123.

%t a[n_] := FromDigits[Flatten@IntegerDigits@(PrimePi[#[[1]]] & /@ FactorInteger[n])]; Table[a[n], {n, 1, 70}]

%Y Cf. A000720, A037916, A080695, A084317, A127668, A304038, A329026.

%K nonn,base

%O 1,3

%A _Ilya Gutkovskiy_, Nov 02 2019

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