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A293013
a(n) = n! * [x^n] exp(x/(1 - x)^n).
4
1, 1, 5, 55, 961, 24101, 818821, 36053515, 1984670465, 132825475081, 10583425959301, 988018789759871, 106673677280748865, 13172700275176482925, 1842428769970603518341, 289406832942160060794451, 50677793314733587473331201, 9829328870566195730521433105
OFFSET
0,3
COMMENTS
Conjecture: a(n+k) == a(n) (mod k) for all n and k. If true, then for each k, the sequence a(n) taken modulo k is a periodic sequence and the period divides k. - Peter Bala, Mar 12 2023
LINKS
FORMULA
a(n) = A293012(n,n).
MATHEMATICA
Table[n! SeriesCoefficient[Exp[x/(1 - x)^n] , {x, 0, n}], {n, 0, 17}]
CROSSREFS
Main diagonal of A293012. Cf. A361281.
Sequence in context: A141357 A357394 A093352 * A195513 A172493 A155807
KEYWORD
nonn,easy
AUTHOR
Ilya Gutkovskiy, Sep 28 2017
STATUS
approved