OFFSET
0,2
COMMENTS
A sequence of palindromic numbers.
LINKS
Colin Barker, Table of n, a(n) for n = 0..333 (corrected by Michel Marcus, Jan 19 2019)
John Rafael M. Antalan, A Recreational Application of Two Integer Sequences and the Generalized Repetitious Number Puzzle, arXiv:1908.06014 [math.HO], 2019.
Eric Weisstein's World of Mathematics, Palindromic Number.
Index entries for linear recurrences with constant coefficients, signature (1001,-1000).
FORMULA
a(n) = (1000^(n + 1) - 1)/999.
a(n) = 1001*a(n-1) - 1000*a(n-2). - Colin Barker, Aug 24 2015
G.f.: 1 / ((x-1)*(1000*x-1)). - Colin Barker, Aug 24 2015
E.g.f.: (1/999)*(1000000*exp(1000*x) - exp(x)). - G. C. Greubel, Aug 29 2015
EXAMPLE
From Bruno Berselli, Aug 25 2015: (Start)
a(n) is the binary representation of A023001
-------------------------------------------------
1 ........................................... 1
1001 ........................................ 9
1001001 ..................................... 73
1001001001 ................................ 585
1001001001001 ............................ 4681
1001001001001001 ........................ 37449
1001001001001001001 .................... 299593
1001001001001001001001 ................ 2396745
1001001001001001001001001 ............ 19173961, etc.
(End)
MATHEMATICA
Table[(1000^(n + 1) - 1)/999, {n, 0, 15}]
LinearRecurrence[{1001, -1000}, {1, 1001}, 20] (* Vincenzo Librandi, Aug 24 2015 *)
PROG
(PARI) Vec(1 / ((x-1)*(1000*x-1)) + O(x^20)) \\ Colin Barker, Aug 24 2015
(Magma) [(1000^(n+1)-1)/999: n in [0..30]]; // Vincenzo Librandi, Aug 24 2015
CROSSREFS
KEYWORD
nonn,base,easy
AUTHOR
Ilya Gutkovskiy, Aug 24 2015
STATUS
approved