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A256303
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Apply the transformation 0 -> 1 -> 2 -> 0 to the digits of n written in base 3; do not convert back to base 10.
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8
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1, 2, 0, 21, 22, 20, 1, 2, 0, 211, 212, 210, 221, 222, 220, 201, 202, 200, 11, 12, 10, 21, 22, 20, 1, 2, 0, 2111, 2112, 2110, 2121, 2122, 2120, 2101, 2102, 2100, 2211, 2212, 2210, 2221, 2222, 2220, 2201, 2202, 2200, 2011, 2012, 2010, 2021, 2022, 2020, 2001
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OFFSET
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0,2
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COMMENTS
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LINKS
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EXAMPLE
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a(3) = 21 because 3 = "10" (in base 3) becomes "21".
a(8) = 0 because 8 = "22" (in base 3) becomes "00".
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MATHEMATICA
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Table[FromDigits[IntegerDigits[n, 3]/.{0->1, 1->2, 2->0}], {n, 0, 60}] (* Harvey P. Dale, Jun 17 2022 *)
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PROG
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(PARI) A256303(n, b=3)=!n+eval(Strchr(apply(d->(d+1)%b+48, digits(n, b))))
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CROSSREFS
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KEYWORD
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nonn,base,easy
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AUTHOR
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STATUS
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approved
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