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A245231 Maximum frustration of complete bipartite graph K(n,4). 5
0, 2, 3, 4, 5, 7, 8, 10, 10, 12, 13, 14, 15, 17, 18, 20, 20, 22, 23, 24, 25, 27, 28, 30, 30, 32, 33, 34, 35, 37, 38, 40, 40, 42, 43, 44, 45, 47, 48, 50, 50, 52, 53, 54, 55, 57, 58, 60, 60, 62, 63, 64, 65, 67, 68, 70, 70, 72, 73, 74, 75, 77, 78, 80, 80, 82, 83, 84, 85, 87, 88, 90, 90, 92, 93, 94, 95, 97, 98, 100 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
The maximum frustration of a graph is the maximum cardinality of a set of edges that contains at most half the edges of any cut-set. Another term that is used is "line index of imbalance". It is also equal to the covering radius of the coset code of the graph.
LINKS
G. S. Bowlin, Maximum Frustration in Bipartite Signed Graphs, Electr. J. Comb. 19(4) (2012) #P10.
R. L. Graham and N. J. A. Sloane, On the Covering Radius of Codes, IEEE Trans. Inform. Theory, IT-31(1985), 263-290
P. Solé and T. Zaslavsky, A Coding Approach to Signed Graphs, SIAM J. Discr. Math 7 (1994), 544-553
FORMULA
a(n) = floor(5*n/4) - 1 if n == 1, 4 or 5 mod 8,
a(n) = floor(5*n/4) otherwise.
G.f. x^2*(2*x^6+x^5+2*x^4+x^3+x^2+x+2)/(x^9-x^8-x+1).
a(n+8) = a(n) + 10.
a(n) = A245230(max(n,4), min(n,4)).
EXAMPLE
For n=2 a set of edges that attains the maximum cardinality a(2)=2 is {(1,3),(1,4)}.
MAPLE
A:= n -> floor(5*n/4) - piecewise(member(n mod 8, {1, 4, 5}), 1, 0);
seq(A(n), n=1..100);
MATHEMATICA
a[n_] := Floor[5n/4] - If[MemberQ[{1, 4, 5}, Mod[n, 8]], 1, 0];
Array[a, 100] (* Jean-François Alcover, Mar 28 2019, from Maple *)
CROSSREFS
Sequence in context: A111747 A257594 A101545 * A034154 A039262 A039202
KEYWORD
nonn
AUTHOR
Robert Israel, Jul 14 2014
STATUS
approved

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Last modified May 6 07:22 EDT 2024. Contains 372290 sequences. (Running on oeis4.)