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A241648
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Numbers m such that the GCD of the x's that satisfy sigma(x)=m is 3.
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5
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4, 124, 320, 392, 416, 800, 1352, 1520, 2912, 2960, 3536, 3872, 5720, 5936, 6320, 7112, 8216, 9176, 9912, 10472, 11816, 12152, 12896, 13280, 14960, 15176, 16080, 16400, 16536, 18032, 18392, 18560, 19136, 19880, 20000, 21632, 21680, 21920, 22736, 23120, 23816
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OFFSET
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1,1
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LINKS
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EXAMPLE
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We have sigma(48)=sigma(75)=124, and gcd(48, 75) = 3, hence 124 is in the sequence.
Likewise, we have sigma(x)=2912 for x=[1116, 1236, 1701, 2007, 2181], with gcd 3.
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MAPLE
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N:= 10^5: # for terms <= N
V:= Vector(N):
for x from 1 to N do
s:= numtheory:-sigma(x);
if s <= N then
if V[s] = 0 then V[s]:= x
else V[s]:= igcd(V[s], x)
fi
fi
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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