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A239351
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Integer solutions x, y, z of x^3 + y^3 + z^3 = 3 with |x| <= |y| <= |z|.
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0
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OFFSET
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1,4
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COMMENTS
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It is conjectured that no other solution exists.
Cassels proved that x == y == z (mod 9), noting first that x == y == z == 1 (mod 3) and then using the law of cubic reciprocity.
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LINKS
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EXAMPLE
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1^3 + 1^3 + 1^3 = 3 = 4^3 + 4^3 + (-5)^3.
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CROSSREFS
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KEYWORD
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sign,hard,more
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AUTHOR
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STATUS
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approved
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