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A217202
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Triangle read by rows, arising in enumeration of permutations by cyclic valleys, cycles and fixed points.
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1
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0, 1, 2, 7, 2, 28, 16, 131, 118, 16, 690, 892, 272, 4033, 7060, 3468, 272, 25864, 58608, 41088, 7936, 180265, 510812, 479772, 156176, 7936, 1354458, 4675912, 5635224, 2665184, 353792, 10898823, 44918110, 67238764, 42832648, 9972704, 353792, 93407828, 452104928
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OFFSET
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1,3
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COMMENTS
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See Ma (2012) for precise definition (cf. Proposition 6).
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LINKS
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EXAMPLE
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Triangle begins:
0;
1;
2;
7, 2;
28, 16;
131, 118, 16;
690, 892, 272;
...
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MATHEMATICA
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V[0][_, _] = 1; V[1][_, _] = 0; V[2][_, x_] := x; V[3][_, x_] := 2x;
V[n_][q_, x_] := V[n][q, x] = (n-1) q V[n-1][q, x] + 2q(1-q) D[V[n-1][q, x], q] + 2x (1-q) D[V[n-1][q, x], x] + (n-1) x V[n-2][q, x] // Simplify;
Table[If[n==1, {0}, CoefficientList[V[n][q, x] /. x -> 1, q]], {n, 1, 13}] // Flatten (* Jean-François Alcover, Sep 23 2018 *)
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PROG
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(PARI) tabf(m) = {P = x; M = subst(P, x, 1); for (d=0, poldegree(M, q), print1(polcoeff(M, d, q), ", "); ); print(""); Q = 2*x; M = subst(Q, x, 1); for (d=0, poldegree(M, q), print1(polcoeff(M, d, q), ", "); ); print(""); for (n=3, m, newP = n*q*Q + 2*q*(1-q)*deriv(Q, q) + 2*x*(1-q)*deriv(Q, x) + n*x*P; M = subst(newP, x, 1); for (d=0, poldegree(M, q), print1(polcoeff(M, d, q), ", "); ); print(""); P = Q; Q = newP; ); } \\ Michel Marcus, Feb 09 2013
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CROSSREFS
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KEYWORD
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nonn,tabf
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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