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A171407 This is a sequence demonstrating a congruence property of second order exponential functions. Let f(n) = a^(b^n) + c where a,b,c & n belong to N, a, b & c fixed. Then f(n + k*phi(phi(f(n)) is congruent to 0 (mod(f(n)). Here k belongs to N. This is a sequence of quotients generated by f(n + k*f(n))/f(n) when a & b = 2, c= 3 and n = 1. when a & b = 2 and c =3 when n = 1. 0
37, 613566757, 48611766702991209066196372490252601637 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
The name contains an unmatched parenthesis. - Editors, Mar 13 2024
LINKS
EXAMPLE
a(n) = 2^2^n + 3 = 7 when n = 1. phi(phi(7)) = 2. 2^2^(1 + 2*k) + 3 = 259; 259/7 = 37.
PROG
(PARI) a(k)=(2^2^(1 + 2*k) + 3)/7
CROSSREFS
Sequence in context: A238840 A345467 A329226 * A023930 A022072 A351221
KEYWORD
nonn,uned,bref
AUTHOR
A.K. Devaraj, Dec 08 2009
STATUS
approved

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Last modified April 28 04:16 EDT 2024. Contains 372020 sequences. (Running on oeis4.)