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A157079
a(n) = 32805000*n^2 - 10513800*n + 842401.
6
23133601, 111034801, 264546001, 483667201, 768398401, 1118739601, 1534690801, 2016252001, 2563423201, 3176204401, 3854595601, 4598596801, 5408208001, 6283429201, 7224260401, 8230701601, 9302752801, 10440414001, 11643685201
OFFSET
1,1
COMMENTS
The identity (32805000*n^2 - 10513800*n + 842401)^2 - (2025*n^2 - 3401*n + 1428)*(729000*n - 116820)^2 = 1 can be written as a(n)^2 - A156854(n)*A156866(n)^2 = 1.
FORMULA
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3).
G.f.: x*(23133601 + 41633998*x + 842401*x^2)/(1-x)^3.
E.g.f.: -842401 + (842401 + 22291200*x + 32805000*x^2)*exp(x). - G. C. Greubel, Jan 27 2022
MATHEMATICA
LinearRecurrence[{3, -3, 1}, {23133601, 111034801, 264546001}, 40]
PROG
(Magma) I:=[23133601, 111034801, 264546001]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..40]];
(PARI) a(n)=32805000*n^2-10513800*n+842401 \\ Charles R Greathouse IV, Dec 23 2011
(Sage) [16200*n*(2025*n - 649) + 842401 for n in (1..30)] # G. C. Greubel, Jan 27 2022
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Feb 22 2009
STATUS
approved