OFFSET
1,3
COMMENTS
a(n) = Sum(k*A119469(n+1,k),k>=0).
For n>1, a(n-1) is the n-th antidiagonal sum of A213777. [Clark Kimberling, Jun 21 2012]
LINKS
M. Janjic, Hessenberg Matrices and Integer Sequences , J. Int. Seq. 13 (2010) # 10.7.8.
A. F. Y. Zhao, Pattern Popularity in Multiply Restricted Permutations, Journal of Integer Sequences, 17 (2014), #14.10.3.
Index entries for linear recurrences with constant coefficients, signature (3,0,-5,0,3,1).
FORMULA
G.f.: z^2*(1+2z)/(1-z-z^2)^3.
EXAMPLE
a(4)=15 because the Fibonacci binary words of length 4 are 1110, 1111, 1101, 1010, 1011, 0110, 0111, 0101 and the positions of those 1's that are followed by a 0 are 3, 2, 1, 3, 1, 3 and 2; their sum is 15.
MAPLE
G := z^2*(1+2*z)/(1-z-z^2)^3: Gser := series(G, z = 0, 38): seq(coeff(Gser, z, n), n = 1 .. 34);
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Emeric Deutsch, Jan 04 2009
STATUS
approved