|
|
A152723
|
|
In binary, count of least frequent bit of n.
|
|
2
|
|
|
0, 1, 0, 1, 1, 1, 0, 1, 2, 2, 1, 2, 1, 1, 0, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 1, 2, 1, 1, 0, 1, 2, 2, 3, 2, 3, 3, 2, 2, 3, 3, 2, 3, 2, 2, 1, 2, 3, 3, 2, 3, 2, 2, 1, 3, 2, 2, 1, 2, 1, 1, 0, 1
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,9
|
|
COMMENTS
|
Express n in binary, then a(n) is the smaller of the number of 0's and the number of 1's;
a(n) + A152724(n) = 1 + floor(log[2](n)).
|
|
LINKS
|
|
|
EXAMPLE
|
a(35) = 3, since 35 in binary is 100011.
|
|
MATHEMATICA
|
Table[Min[DigitCount[n, 2, 1], DigitCount[n, 2, 0]], {n, 70}] (* Harvey P. Dale, May 09 2012 *)
|
|
PROG
|
(Haskell)
a152723 n = min (a000120 n) (a023416 n)
(PARI) a(n) = my(x=hammingweight(n)); min(x, #binary(n) - x); \\ Michel Marcus, Mar 30 2020
|
|
CROSSREFS
|
Cf. A092431 (positions of records).
|
|
KEYWORD
|
base,easy,nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|