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A126188
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Triangle read by rows: T(n,k) is the number of hex trees with n edges and k pairs of adjacent vertices of outdegree 2.
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2
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1, 3, 10, 36, 135, 2, 519, 24, 2034, 180, 5, 8100, 1110, 75, 32688, 6210, 675, 14, 133380, 32886, 4851, 252, 549342, 168210, 30996, 2646, 42, 2280690, 840132, 184842, 21672, 882, 9534591, 4124682, 1053486, 154980, 10584, 132, 40103019
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OFFSET
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0,2
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COMMENTS
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A hex tree is a rooted tree where each vertex has 0, 1, or 2 children and, when only one child is present, it is either a left child, or a middle child, or a right child (name due to an obvious bijection with certain tree-like polyhexes; see the Harary-Read reference).
Row n has floor(n/2) terms (n>=2).
Sum of terms in row n = A002212(n+1).
Sum_{k=0..floor(n/2)-1} k*T(n,k) = A126190(n).
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LINKS
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FORMULA
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G.f.: G = G(t,z) = 1+3*z*G+z^2*(1+3*z*G+t*(G-1-3*z*G))^2 (explicit expression in the Maple program).
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EXAMPLE
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Triangle starts:
1;
3;
10;
36;
135, 2;
519, 24;
2034, 180, 5;
8100, 1110, 75;
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MAPLE
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G:=1/2*(12*z^3*t+2*z^2*t^2-2*z^2*t-6*z^3*t^2-3*z-6*z^3+1-sqrt(1+9*z^2-4*z^2*t-6*z+12*z^3*t-12*z^3))/z^2/(3*z*t-t-3*z)^2: Gser:=simplify(series(G, z=0, 18)): for n from 0 to 14 do P[n]:=sort(coeff(Gser, z, n)) od: 1; 3; for n from 2 to 14 do seq(coeff(P[n], t, j), j=0..floor(n/2)-1) od;
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MATHEMATICA
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g[t_, z_] = G /. Solve[G == 1 + 3z*G + z^2*(1 + 3z*G + t*(G - 1 - 3z*G))^2, G][[1]]; Flatten[ CoefficientList[ CoefficientList[ Series[g[t, z], {z, 0, 13}], z], t]][[1 ;; 39]] (* Jean-François Alcover, May 27 2011, after g.f. *)
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CROSSREFS
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KEYWORD
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nonn,tabf
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AUTHOR
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STATUS
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approved
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