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A121343 a(n) = Fibonacci(n) mod n(n+1)/2. 4
0, 0, 1, 2, 3, 5, 8, 13, 21, 34, 0, 23, 66, 51, 62, 10, 35, 67, 19, 1, 45, 89, 1, 229, 168, 275, 298, 236, 319, 59, 155, 125, 309, 376, 407, 485, 630, 628, 419, 466, 615, 370, 517, 343, 663, 830, 988, 1033, 168, 624, 700, 746, 1167, 158, 872, 1105, 609, 610, 59, 1181, 0, 1, 125 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,4
LINKS
FORMULA
A000045(n) modulo A000217(n).
EXAMPLE
a(11)=23 since Fib(11)=89==23(mod (11*12/2)).
MAPLE
a:= proc(n) local r, M, p, m; r, M, p, m:=
<<1|0>, <0|1>>, <<0|1>, <1|1>>, n, n*(n+1)/2;
do if irem(p, 2, 'p')=1 then r:= r.M mod m fi;
if p=0 then break fi; M:= M.M mod m
od; r[1, 2]
end:
seq(a(n), n=0..100); # Alois P. Heinz, Nov 26 2016
MATHEMATICA
f[n_] := If[n == 0, 0, Mod[Fibonacci@n, n(n + 1)/2]]; f /@ Range[0, 62] (* Robert G. Wilson v, Aug 31 2006 *)
Join[{0}, Mod[First[#], Last[#]]&/@With[{nn=70}, Thread[{Fibonacci[ Range[ nn]], Accumulate[Range[nn]]}]]] (* Harvey P. Dale, May 21 2012 *)
PROG
(PARI) fibmod(n, m)=((Mod([1, 1; 1, 0], m))^n)[1, 2]
a(n)=lift(fibmod(n, n*(n+1)/2)) \\ Charles R Greathouse IV, Jun 20 2017
CROSSREFS
Sequence in context: A280198 A175712 A013986 * A321021 A236768 A023439
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, Aug 29 2006
EXTENSIONS
Edited by N. J. A. Sloane, Jul 01 2008 at the suggestion of R. J. Mathar
STATUS
approved

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Last modified April 19 16:21 EDT 2024. Contains 371794 sequences. (Running on oeis4.)