|
|
A119627
|
|
Number of labeled graphs with no isolated nodes of size up to n+1 nodes, using 2*n+2 unique labels (no two nodes can have the same label).
|
|
0
|
|
|
6, 95, 3122, 202671, 25992373, 6561168159, 3271778102626, 3238332198581151, 6386927543425690577, 25167828012974622494207, 198457647877828107872246829, 3134149754118486012018252515615
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
Replacing 2*n+2 in the formula with m gives the formula to calculate the number of labeled graphs with no isolated nodes of size up to n+1 nodes, using m unique labels (with m > n). An alternative (and much more complicated!) way to find the sequence is with the following recurrence (n>1, m>n): a(n,m)=a(n-1,m)+binomial(m,n)*(-a(n-1,n+1)+sum_{k=1..n*(n+1)/2}binomial(n*(n+1)/2,k)), a(2,m)=binomial(m,2)+binomial(m,3)+binomial(3,2)*binomial(m,3).
|
|
LINKS
|
|
|
FORMULA
|
a(n)=sum_{k=1..n+1}binomial(2*n+2,k)*A006129(k)
|
|
EXAMPLE
|
a(1)=6 because with 1+1 nodes and 2*1+2 labels, you can construct the following graphs: 1-2, 1-3, 1-4, 2-3, 2-4, 3-4. We have 6 different graphs.
|
|
MAPLE
|
A006125:=(n)->2^(n*(n-1)/2); A006129:=(n)->sum('binomial(n, i)*(-1)^i*A006125(n-i)', i=0..n); A:=(n)->sum('binomial(2*n+2, i)*A006129(i)', i=1..n+1);
|
|
CROSSREFS
|
|
|
KEYWORD
|
easy,nonn
|
|
AUTHOR
|
Delorme C. (delorme(AT)lri.fr), Lopez R. (lopez(AT)lri.fr), Soguet D. (soguet(AT)lri.fr) Jun 08 2006
|
|
STATUS
|
approved
|
|
|
|