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A102602
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a(n) = least k such that ((m+1)^k)*(m^k-1) - 1 is prime, with m = 2n+1, or 0 if no such k exists.
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0
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1, 1, 1, 1, 4, 1, 1, 50, 1, 1, 2, 4, 1, 1, 3, 1, 1, 1, 2, 9, 1, 4, 1, 1, 9, 36, 1, 158, 45, 1, 1, 10, 4, 1, 1, 3, 1, 1, 3, 5, 2, 6, 2, 1, 3, 1, 2, 2, 4, 2, 1, 15, 1, 4, 8, 2, 2, 1, 1, 1, 14, 5, 1
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OFFSET
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1,5
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COMMENTS
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For n=64 (m=129), k > 2000 if k exists.
When k=1, the prime is of the form 4*n^2 + 4*n - 1 (or m^2 - 2).
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LINKS
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MATHEMATICA
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f[n_] := Block[{k = 1}, While[ !PrimeQ[((n + 1)^k)*(n^k - 1) - 1], k++ ]; k]; Table[ f[n], {n, 3, 128, 2}] (* Robert G. Wilson v, Aug 06 2005 *)
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PROG
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(PARI) a(n) = {my(k = 1); my(m = 2*n+1); while(! isprime((m+1)^k*(m^k-1) - 1), k++; ); k; } \\ Michel Marcus, Feb 06 2014
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CROSSREFS
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KEYWORD
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more,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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