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A098155
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Summarize the previous term in base 4 (in increasing order).
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2
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1, 11, 21, 1112, 3112, 211213, 312213, 212223, 1110213, 101011213, 201111213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213, 101112213
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,2
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COMMENTS
| Let a(1)=1. Describing a(1) as "one 1" again gives a(2)=11 (same digit string as A005151 and similar sequences). Likewise, a(3) through a(8) have the same digit strings as the corresponding terms of A005151, but describing a(8) as "one 1, four 2s, one 3" gives a(9)=1110213 when the frequency of digit occurrence is written in base 4 and followed by the digit counted.
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FORMULA
| a(n) = 101112213 for all n >= 12 (see example).
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EXAMPLE
| Summarizing a(12) = 101112213 in increasing digit order, there are "one 0, five 1's, two 2s, one 3", so concatenating 1 0 11 1 2 2 1 3 gives a(13) = 101112213 (=a(14)=a(15)=...).
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CROSSREFS
| Cf. A098153 (binary), A098154 (ternary), A005151 (decimal and digit strings for all other bases b >= 5).
Sequence in context: A138485 A006711 A005151 * A098154 A158081 A007890
Adjacent sequences: A098152 A098153 A098154 * A098156 A098157 A098158
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KEYWORD
| base,easy,nonn
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AUTHOR
| Rick L. Shepherd (rshepherd2(AT)hotmail.com), Aug 29 2004
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