1,1
Algorithm: 1# factorize n; 2# arrange prime-factors by decreasing size; 3# concatenate prime factors and interpret the result as decimal number.Iterate 1#, 2#, 3#.
n=213 gives {213,713,3123,3473,15123,713},
n=323 gives {323,1917,713,3123,3473,15123,713}
n=639 gives {639,713,3123,3473,15123,713}
Cf. A084317-A084319, A085308, A085309.
Sequence in context: A138568 A201104 A092126 * A092127 A082967 A201342
Adjacent sequences: A085306 A085307 A085308 * A085310 A085311 A085312
base,nonn
Labos E. (labos(AT)ana.sote.hu), Jun 27 2003