OFFSET
1,1
COMMENTS
n is in the sequence if y=(xn+1)/(x+n) is an integer for some integer x where 1<x<n.
PROG
(PARI) for(n=1, 120, x=1; b=0; while(x<n, x=x+1; r=(x+n)*floor((x*n+1)/(x+n)); if(r>=(x*n+1), b=b+1)); if(b>0, print1(n, ", ")))
CROSSREFS
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Jun 12 2003
STATUS
approved