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A083679
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Decimal expansion of log(4/3).
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5
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2, 8, 7, 6, 8, 2, 0, 7, 2, 4, 5, 1, 7, 8, 0, 9, 2, 7, 4, 3, 9, 2, 1, 9, 0, 0, 5, 9, 9, 3, 8, 2, 7, 4, 3, 1, 5, 0, 3, 5, 0, 9, 7, 1, 0, 8, 9, 7, 7, 6, 1, 0, 5, 6, 5, 0, 6, 6, 6, 5, 6, 8, 5, 3, 4, 9, 2, 9, 2, 9, 5, 0, 7, 2, 0, 7, 8, 0, 4, 6, 4, 3, 3, 8, 1, 1, 0, 8, 9, 9, 1, 7, 9, 1, 0, 5, 2, 8, 6, 2, 9, 6, 0, 3
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OFFSET
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0,1
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LINKS
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FORMULA
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Limit of a special sum: log(4/3) = Sum_{k>=1} (Sum_{i=1..k} 1/(i*2^i))/2^(k+1).
Asymptotically: log(4/3) = Sum_{k=1..n} (Sum_{i=1..k} 1/(i*2^i))/2^(k+1) + log(2)/2^(n+1) + o(1/2^n).
Equals 2 * arctanh(1/7).
Equals Sum_{n>=1} 1/(n * 4^n) = Sum_{n>=1} 1/A018215(n).
Equals Sum_{n>=1} (-1)^(n+1)/(n * 3^n) = Sum_{n>=1} (-1)^(n+1)/A036290(n).
Equals Integral_{x=0..oo} 1/(3*exp(x) + 1) dx. (End)
log(4/3) = 2*Sum_{n >= 1} 1/(n*P(n, 7)*P(n-1, 7)), where P(n, x) denotes the n-th Legendre polynomial. The first 10 terms of the series gives the approximation log(4/3) = 0.28768207245178092743921(31...), correct to 23 decimal places. - Peter Bala, Mar 18 2024
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EXAMPLE
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log(4/3) = 0.2876820724517809274392190059938274315035097108977610565....
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MATHEMATICA
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PROG
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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