OFFSET
1,1
COMMENTS
From David A. Corneth, Aug 30 2019: (Start)
As (m+1)*(m+2)*...*(m+n) is the product of n consecutive integers, it's divisible by n! and so a(n) >= 2^A011371(n) = A060818(n).
None of m+1..m+n are prime. (End)
LINKS
David A. Corneth, Table of n, a(n) for n = 1..75
EXAMPLE
MATHEMATICA
k = 1; lc = 1; Do[While[lc = LCM[lc, k]; Mod[lc, (n + k)!/k! ] != 0, k++ ]; Print[{n, k}], {n, 0, 50}] (* Robert G. Wilson v, Apr 12 2006 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Labos Elemer, Apr 10 2003
EXTENSIONS
a(16)-a(19) from Robert G. Wilson v, Apr 12 2006
a(20)-a(23) from Vaclav Kotesovec, Aug 30 2019
a(24)-a(37) from David A. Corneth, Aug 30 2019
STATUS
approved