A081836 Let z(n) be the golden ratio (phi) truncated to n decimal digits; sequence gives maximum element in the continued fraction for z(n).

2, 3, 5, 5, 6, 129, 15, 7, 10, 36, 65, 155, 70, 40, 20, 1122, 13, 15, 52, 52, 10, 19, 8, 87, 69, 42, 41, 30, 2036, 131, 86, 26, 41, 65, 231, 58, 161, 94, 94, 137, 137, 1323, 97, 14, 282, 15, 15, 122, 137, 80, 329, 164, 124, 748, 175, 7389, 2164, 101, 255, 201, 34, 17

Offset

1,1

Links

Table of n, a(n) for n=1..62.

Example

phi=(1+sqrt(5))/2=1.6180339887498948482045... so z(10)=1.6180339887 and the continued fraction for z(10) is [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 5, 2, 1, 1, 4, 1, 10, 36, 2], hence a(10)=36.

Crossrefs

Sequence in context: A163831 A326399 A192419 * A263721 A351259 A154290

Adjacent sequences: A081833 A081834 A081835 * A081837 A081838 A081839

Keyword

base,nonn

Author

Benoit Cloitre, Apr 11 2003

Status

approved