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A081769
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a(n)-th term of the continued fraction for sum(k>=0,1/2^(2^k)) is 2.
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0
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5, 13, 18, 23, 25, 30, 38, 43, 45, 53, 58, 60, 65, 70, 78, 83, 85, 93, 98, 103, 105, 110, 118, 120, 125, 133, 138, 140, 145, 150, 158, 163, 165, 173, 178, 183, 185, 190, 198, 203, 205, 213, 218, 220, 225, 230, 238, 240, 245, 253, 258, 263, 265, 270, 278, 280
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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FORMULA
| a(n)=5*n + 0 or + 3 and it appears that a(n)=5*n+3*A073089(n+2)
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EXAMPLE
| The continued fraction for sum(k>=0,1/2^(2^k)) is : 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1... hence a(1)=5
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CROSSREFS
| Cf. A006466, A073089.
Sequence in context: A125146 A051900 A120062 * A188030 A101864 A190432
Adjacent sequences: A081766 A081767 A081768 * A081770 A081771 A081772
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KEYWORD
| easy,nonn
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AUTHOR
| Benoit Cloitre (benoit7848c(AT)orange.fr), Apr 09 2003
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