OFFSET
1,1
FORMULA
a(n)=5*n + 0 or + 3 and it appears that a(n)=5*n+3*A073089(n+2)
EXAMPLE
The continued fraction for sum(k>=0,1/2^(2^k)) is : 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1... hence a(1)=5
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Benoit Cloitre, Apr 09 2003
STATUS
approved