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 A072894 Let c(k) be defined as follows: c(1)=1, c(2)=n, c(k+2) = c(k+1)/2 + c(k)/2 if c(k+1) and c(k) have the same parity; c(k+2) = c(k+1)/2 + c(k)/2 + 1/2 otherwise; a(n) = limit_{ k -> infinity} c(k). 2
 1, 2, 3, 4, 4, 5, 6, 7, 7, 8, 9, 10, 10, 11, 11, 12, 12, 13, 14, 15, 15, 16, 17, 18, 18, 19, 20, 21, 21, 22, 22, 23, 23, 24, 25, 26, 26, 27, 28, 29, 29, 30, 31, 32, 32, 33, 33, 34, 34, 35, 36, 37, 37, 38, 38, 39, 39, 40, 41, 42, 42, 43, 43, 44, 44, 45, 46, 47, 47, 48, 49, 50, 50 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Conjectures : (1) a(n+1)-a(n) = 0 or 1; (2) lim n ->infinity a(n)/n = 2/3; (3) 1/2 < (3a(n)-2n)/Log(n) <3/2 for any n > 1000. Does lim n -> infinity (3a(n)-2n)/Log(n) = 1 ? LINKS EXAMPLE If n=5, c(3)=(1+5)/2=3, c(4)=(3+5)/2=4, c(5)=(4+3+1)/2=4, ..., hence a(5)=4. CROSSREFS First differences are in A098725. Sequence in context: A025528 A255338 A123580 * A328309 A037915 A195180 Adjacent sequences:  A072891 A072892 A072893 * A072895 A072896 A072897 KEYWORD easy,nonn AUTHOR Benoit Cloitre, Jul 29 2002 STATUS approved

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Last modified August 11 07:36 EDT 2022. Contains 356055 sequences. (Running on oeis4.)