|
| |
|
|
A061462
|
|
The exact power of 2 that divides the n-th Bell number (A000110). Has period 12.
|
|
1
|
|
|
|
1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2, 1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2, 1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2, 1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2, 1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2, 1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2, 1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2, 1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2, 1, 1, 2, 1, 1, 4, 1, 1, 4, 1, 1, 2
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
|
OFFSET
|
0,3
|
|
|
COMMENTS
|
{ Bell(n) mod 8 } is periodic with period 24, the period being (1 1 2 5 7 4 3 5 4 3 7 2 5 5 2 1 3 4 7 1 4 7 3 2). Hence the highest power of 2 dividing a Bell number is 4. - David W. Wilson, Jun 29, 2001
|
|
|
REFERENCES
|
W. F. Lunnon, P. A. B. Pleasants and N. M. Stephens, Arithmetic properties of Bell numbers to a composite modulus I, Acta Arithmetica 35 (1979) 1-16.
|
|
|
LINKS
|
Table of n, a(n) for n=0..107.
|
|
|
FORMULA
|
a(n)=(1/396)*{43*(n mod 12)-23*[(n+1) mod 12]+10*[(n+2) mod 12]+109*[(n+3) mod 12]-89*[(n+4) mod 12]+10*[(n+5) mod 12]+109*[(n+6) mod 12]-89*[(n+7) mod 12]+10*[(n+8) mod 12]+43*[(n+9) mod 12]-23*[(n+10) mod 12]+10*[(n+11) mod 12]}, with n>=0 [From Paolo P. Lava, Oct 22 2008]
|
|
|
CROSSREFS
|
Cf. A000110.
Sequence in context: A099238 A141450 A209690 * A122578 A208648 A005131
Adjacent sequences: A061459 A061460 A061461 * A061463 A061464 A061465
|
|
|
KEYWORD
|
nonn
|
|
|
AUTHOR
|
Ahmed Fares (ahmedfares(AT)my-deja.com), Jun 10 2001
|
|
|
STATUS
|
approved
|
| |
|
|
