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A050221
a(n) = number of sets of consecutive primes whose arithmetic mean is A060863(n).
4
1, 1, 1, 2, 1, 1, 2, 1, 3, 1, 3, 2, 2, 1, 1, 2, 2, 2, 2, 5, 2, 3, 2, 4, 2, 1, 3, 2, 1, 1, 2, 2, 1, 5, 1, 4, 2, 2, 1, 3, 1, 2, 1, 1, 4, 1, 2, 1, 1, 1, 1, 3, 2, 2, 2, 1, 1, 5, 3, 1, 1, 1, 2, 2, 2, 1, 1, 3, 3, 1, 4, 1, 2, 2, 1, 3, 3, 1, 3, 1, 2, 1, 1, 3, 1, 1, 1, 2, 1, 3, 1, 1, 1, 2, 3, 1, 1, 2, 4, 4, 2, 4, 1, 3, 2
OFFSET
1,4
COMMENTS
Essentially A122821 with the 0's removed.
FORMULA
a(n) = A122821(A060863(n)).
EXAMPLE
For n=4; A060863(4) = 5. the two sets are 5/1 = 5, (3+5+7)/3 = 5. so a(4)=2.
MATHEMATICA
f[n_]:=Block[{i=1, j, c=0, m}, While[Prime[i]<=n, j=1; While[m=Sum[Prime[k], {k, i, i+j-1}]/j; If[m==n, c++ ]; m<n, j++ ]; i++ ]; c]; Select[Table[f[n], {n, 160}], #>0&] (* Ray Chandler, Oct 03 2006 *)
CROSSREFS
Sequence in context: A247299 A127586 A055893 * A213235 A113279 A213234
KEYWORD
easy,nonn
AUTHOR
Naohiro Nomoto, May 08 2003
EXTENSIONS
Extended by Ray Chandler, Oct 03 2006
STATUS
approved