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A022916
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Multinomial coefficient n!/([n/3]![(n+1)/3]![(n+2)/3]!).
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7
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1, 1, 2, 6, 12, 30, 90, 210, 560, 1680, 4200, 11550, 34650, 90090, 252252, 756756, 2018016, 5717712, 17153136, 46558512, 133024320, 399072960, 1097450640, 3155170590, 9465511770, 26293088250, 75957810500, 227873431500, 638045608200, 1850332263780, 5550996791340
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OFFSET
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0,3
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COMMENTS
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Number of permutation patterns modulo 3. This matches the multinomial formula. - Olivier Gérard, Feb 25 2011
Also the number of permutations of n elements where p(k-3) < p(k) for all k. - Joerg Arndt, Jul 23 2011
Also the number of n-step walks on cubic lattice starting at (0,0,0), ending at (floor(n/3), floor((n+1)/3), floor((n+2)/3)), remaining in the first (nonnegative) octant and using steps (0,0,1), (0,1,0), and (1,0,0). - Alois P. Heinz, Oct 11 2019
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LINKS
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FORMULA
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Recurrence: (n+1)*(n+2)*(3*n+1)*a(n) = 3*(3*n^2 + 3*n + 2)*a(n-1) + 27*(n-1)*(n+2)*a(n-2) + 27*(n-2)*(n-1)*(3*n+4)*a(n-3). - Vaclav Kotesovec, Feb 26 2014
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EXAMPLE
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Starting from n=4, several permutations have the same pattern. Both (3,1,4,2) and (3,4,1,2) have pattern (0, 1, 1, 2) modulo 3.
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MAPLE
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a:= n-> combinat[multinomial](n, floor((n+i)/3)$i=0..2):
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MATHEMATICA
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Table[ n!/(Quotient[n, 3]!*Quotient[n + 1, 3]!*Quotient[n + 2, 3]!), {n, 0, 30}]
Table[n!/Times@@(Floor/@((n+{0, 1, 2})/3)!), {n, 0, 30}] (* Harvey P. Dale, Jul 13 2012 *)
Table[Multinomial[Floor[n/3], Floor[(n+1)/3], Floor[(n+2)/3]], {n, 0, 30}] (* Jean-François Alcover, Jun 24 2015 *)
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PROG
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(PARI) a(n)=n!/((n\3)!*((n+1)\3)!*((n+2)\3)!)
(PARI) {a(n)= if(n<0, 0, n!/(n\3)!/((n+1)\3)!/((n+2)\3)!)} /* Michael Somos, Jun 20 2007 */
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CROSSREFS
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Cf. A001405 (permutation patterns mod 2).
Cf. A022917 (permutation patterns mod 4).
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KEYWORD
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nonn,easy,nice
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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