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A368655 Binomial transform of Gould's sequence (A001316). 2
1, 3, 7, 17, 39, 85, 181, 387, 839, 1829, 3953, 8391, 17461, 35759, 72559, 146921, 298631, 611733, 1265185, 2641351, 5555729, 11735571, 24798755, 52219493, 109213269, 226322799, 464125219, 941694917, 1891879215, 3769497853, 7465462669, 14735667195, 29070011399 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
Consider the multivariate polynomial quotient ring K'_n = Z[x_1, x_2, x_3, ..., x_n]/I where I = <x_1^2 - P_1, x_2^2 - P_2, ..., x_n^2 - P_n> is an ideal in Z[x_1, x_2, x_3, ..., x_n]. Here, each polynomial P_i = -2x_i + x_{i+1} for 0 < i <= n, with x_{n+1} assumed to be 1. In this ring, every variable x_i for 0 < i <= n satisfies the recursive relation x_i^2 = -2x_i + x_{i+1}. The n-th term of this sequence is obtained by expanding the polynomial (2 + x_1)^n within the ring K'_n and evaluating at x_1 = x_2 = ... = x_n = 1. For a detailed explanation and proof, refer to Shunia's paper under links.
LINKS
Joseph M. Shunia, A Polynomial Ring Connecting Central Binomial Coefficients and Gould's Sequence, arXiv:2312.00302 [math.GM], 2023.
FORMULA
a(n) = Sum_{k=0..n} binomial(n,k)*A001316(k).
a(n) = Sum_{k=0..n} binomial(n,k)*2^(A000120(k)).
MATHEMATICA
Table[Sum[Binomial[n, k] * 2^DigitCount[k, 2, 1], {k, 0, n}], {n, 0, 32}] (* Vaclav Kotesovec, Apr 02 2024 *)
PROG
(PARI) {a(n) = sum(k=0, n, binomial(n, k) * 2^hammingweight(k))};
(Sage)
def a(n):
R = PolynomialRing(ZZ, n, 'x')
x = R.gens()
I_list = [x[i]^2 - (-2*x[i] + x[i+1]) if i < n-1 else x[i]^2 for i in range(n)]
I = R.ideal(I_list)
K_n = R.quotient(I, 'x')
p_n = K_n((x[0]+2)^n)
subs_dict = {x[i]: 1 for i in range(n)}
a_n = p_n.lift().subs(subs_dict)
return a_n # Joseph M. Shunia, Mar 22 2024
CROSSREFS
Cf. A000120, A001316 (Gould's sequence).
Sequence in context: A176502 A319003 A141199 * A003478 A119587 A127984
KEYWORD
nonn,easy,changed
AUTHOR
Joseph M. Shunia, Jan 02 2024
STATUS
approved

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Last modified April 28 13:13 EDT 2024. Contains 372086 sequences. (Running on oeis4.)