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a(n) = Sum_{k=0..n} A011971(n, k) * (-2)^(n - k).
2

%I #8 Dec 01 2023 18:50:41

%S 1,0,7,-17,166,-931,8333,-67902,668341,-6733957,74909152,-875130273,

%T 10931723505,-143624036492,1989841289619,-28881136161245,

%U 438657928012966,-6948176832355895,114571387874994353,-1962292996833874918,34849770255925089153,-640681440719312240225,12174584322610783966760

%N a(n) = Sum_{k=0..n} A011971(n, k) * (-2)^(n - k).

%C The Peirce/Aitken polynomials evaluated at -1/2 and the result normalized with (-2)^n.

%o (Python) # Using the function b from A367808.

%o def a(n): return sum(b(n)[k] * (-2) ** (n - k) for k in range(n + 1))

%o print([a(n) for n in range(23)])

%Y Cf. A011971, A367808.

%K sign

%O 0,3

%A _Peter Luschny_, Dec 01 2023