|
%I #32 Jun 06 2022 08:05:40
%S 1,2,1,2,1,3,2,3,2,2,1,2,1,3,1,6,1,4,1,2,1,3,2,3,4,2,2,2,1,4,1,4,1,4,
%T 1,4,1,3,1,3,1,2,2,2,2,3,2,6,2,4,1,4,1,6,1,3,1,2,1,2,2,4,2,4,1,2,1,2,
%U 1,6,1,6,2,2,2,2,1,3,3,3,3,2,1,2
%N Number of solutions (n, D) for Pell equation n^2 - D*y^2 = 1 with fixed n.
%C a(n) can be computed as the number of divisors of the square root of the largest square dividing n^2 - 1.
%C A067874 gives n with a(n) = 1.
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/PellEquation.html">Pell Equation</a>.
%F a(n) = A000005(A000188(n^2-1)).
%e a(17) = 6 because there are 6 possible solutions to 17^2 - D*y^2 = 1: 17^2 - 2*12^2 = 1, 17^2 - 8*6^2 = 1, 17^2 - 18*4^2 = 1, 17^2 - 32*3^2 = 1, 17^2 - 72*2^2 = 1 and 17^2 - 288*1^2 = 1. D = 18 is the smallest of the 6 D values, where the (17,y) pair is minimal and hence A033314(17) = 18.
%t squarefreepart[n_] := Times @@ Power @@@ ({#[[1]], Mod[#[[2]], 2]} & /@ FactorInteger[n]);
%t a[n_] := Divisors[Sqrt[(n^2 - 1)/squarefreepart[n^2 - 1]]] // Length; Table[a[n], {n, 2, 85}]
%o (PARI) f(n) = sqrtint(n/core(n)) \\ A000188
%o a(n) = numdiv(f(n^2-1)); \\ _Michel Marcus_, Jun 05 2022
%Y Cf. A002349, A002350, A033314, A067874.
%K nonn
%O 2,2
%A _Herbert Kociemba_, Jun 04 2022
|
