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Numbers that are the sum of nine fifth powers in exactly five ways.
7

%I #6 Jul 31 2021 19:00:57

%S 392063,392274,406559,458875,519237,538291,607947,663871,672024,

%T 672055,672266,672297,673586,673797,674578,675390,680041,681330,

%U 704582,704822,714299,730260,732603,763027,763324,765873,766417,777820,780099,814082,820887,825678

%N Numbers that are the sum of nine fifth powers in exactly five ways.

%C Differs from A345622 at term 50 because 926404 = 2^5 + 5^5 + 6^5 + 6^5 + 6^5 + 6^5 + 8^5 + 10^5 + 15^5 = 2^5 + 4^5 + 6^5 + 6^5 + 7^5 + 7^5 + 7^5 + 10^5 + 15^5 = 2^5 + 2^5 + 5^5 + 8^5 + 8^5 + 8^5 + 8^5 + 8^5 + 15^5 = 2^5 + 2^5 + 2^5 + 7^5 + 7^5 + 8^5 + 11^5 + 11^5 + 14^5 = 2^5 + 2^5 + 2^5 + 6^5 + 7^5 + 8^5 + 12^5 + 12^5 + 13^5 = 1^5 + 1^5 + 4^5 + 4^5 + 7^5 + 11^5 + 12^5 + 12^5 + 12^5.

%H Sean A. Irvine, <a href="/A346340/b346340.txt">Table of n, a(n) for n = 1..10000</a>

%e 392063 is a term because 392063 = 2^5 + 2^5 + 4^5 + 5^5 + 5^5 + 5^5 + 8^5 + 10^5 + 12^5 = 2^5 + 2^5 + 3^5 + 3^5 + 6^5 + 7^5 + 9^5 + 9^5 + 12^5 = 2^5 + 2^5 + 4^5 + 4^5 + 4^5 + 6^5 + 9^5 + 11^5 + 11^5 = 1^5 + 2^5 + 3^5 + 4^5 + 5^5 + 8^5 + 8^5 + 11^5 + 11^5 = 1^5 + 1^5 + 1^5 + 3^5 + 8^5 + 9^5 + 10^5 + 10^5 + 10^5.

%o (Python)

%o from itertools import combinations_with_replacement as cwr

%o from collections import defaultdict

%o keep = defaultdict(lambda: 0)

%o power_terms = [x**5 for x in range(1, 1000)]

%o for pos in cwr(power_terms, 9):

%o tot = sum(pos)

%o keep[tot] += 1

%o rets = sorted([k for k, v in keep.items() if v == 5])

%o for x in range(len(rets)):

%o print(rets[x])

%Y Cf. A345622, A345847, A346330, A346339, A346341, A346350.

%K nonn

%O 1,1

%A _David Consiglio, Jr._, Jul 13 2021